If the zeroes of polynomial x2 – 3x2 + x + 1 are a - b, a, a + b then value of a is
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Answer.
a−b,a,a+b are zeroes of x
3
−3x
2
+x+1
⇒a−b+a+a+b= sum of zeroes = 3
⇒3a=3
⇒a=1
(a−b)(a)(a+b)= product of zeroes =−1
⇒(1−b)(1+b)=−1
⇒1−b
2
=−1
⇒b
2
=
⇒b=±
√2
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