Question

if the zeroes of quadratic polynomial x square+(a+1)x+b are 2 and -3 then.find the value of a and b. fast on page...no spams
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Answer 1

Answer:-

Given polynomial = x² + (a + 1)x + b = 0

let the zeroes be "p" and "q" (p = 2 & q = -3),

And , a = 1 ; b = a + 1 ; c = b

We know that,

Sum of zeroes (p + q) = - b/a

p + q = -(a + 1)/1

p + q = - a - 1

Substitute values of p & q here,

2 + (-3) = - a - 1

2 - 3 = - a - 1

- 1 + 1 = - a

a = 0

We know that, product of the roots pq = c/a

pq = b/1

(2)(- 3) = b

b = - 6.

Hence, the value of a is 0 and b is -6.