Question

If the zeroes of quadratic polynomial x²+(a+1)x+b are 2 and -3. Then find a and -b​

Answer 1

${\red{\huge{\bf{Hey}}}}$

${\bold{\underline{Given:}}}$

$\alpha + \beta = \frac{ - b}{a} \\ 2 - 3 = \frac{ - (a + 1)}{1} \\ - 1 = - a - 1 \\ a = 0$

$\alpha \beta = \frac{c}{a} \\ 2 \times - 3 = b \\ b = - 6$

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