Math, asked by HarshKilaji, 11 months ago


 | {x}^{2} - 10 |  \leqslant 6

Answers

Answered by Anonymous
1

Hey Ma8,

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 {x}^{2}  - 10 \leqslant 6 \\  {x}^{2}  \leqslant 6 + 10 \\  x\leqslant  \sqrt{16 }  \\ x \:   \leqslant 4

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Anonymous: follow me then i will follow you BACK
HarshKilaji: wrong answer
HarshKilaji: Answer is [-4, -2] U [2, 4]
HarshKilaji: but I want solution
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