if the zeroes of the equation x²+ax+b=0 are a and b then find the value of a and b???
Sachinarjun:
hi
Answers
Answered by
5
sum of zeros = (-coefficient of x)/(coefficient ofx²)
so a+b = (-a/1)
2a+b=0
product of zeros = (constant term/coefficient of x²)
ab =(b/1)
a=1
so b= -2a = -2
so a+b = (-a/1)
2a+b=0
product of zeros = (constant term/coefficient of x²)
ab =(b/1)
a=1
so b= -2a = -2
Similar questions