If the zeroes of the polynomial 3x² -11r+k are reciprocal to each
other, then the value of k is
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Answer:
3x²+8x+K
Let the zeroes be a and 1/a
Product of zeroes = (a)(1/a) = constant/x³ coefficient
1 = K/3
K = 1×3
K = 3
There the given polynomial is 3x²+8x+3
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