If the zeroes of the polynomial x^2+ax+b are double in value the zeroes of the polynomial 4x^2 -6x+3.Find the value of a and b
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Answered by
24
for x²+ax+b = 0
let zeroes are n and m
so
n+m = -a
nm = b
if zeroes of quadratic
4x²-6x+3
are
p and q
then
p+q = 6/4
pq = 3/4
n=2p
m=2q
n+m = 3
nm = 3
then
a = -3
b=3
let zeroes are n and m
so
n+m = -a
nm = b
if zeroes of quadratic
4x²-6x+3
are
p and q
then
p+q = 6/4
pq = 3/4
n=2p
m=2q
n+m = 3
nm = 3
then
a = -3
b=3
kidambisrikanth:
then how it is 3
srry
leave this
can u plz tell how a=-3 and b=3
plz
thanks for ur answers once again
for any quadratic ax²+bx+c=0
sum of zeroes = -b/a
product of roots = c/a
and zeroes and roots are same thing
Answered by
2
Answer:
0
Step-by-step explanation:
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