Question

The root of the equation x+4/4+x-5/3=11 is

Answer 1

3x+12+4x-20/12=11
7x-8=11×12
7x=132+8
x=140/7
x=20
is your answer

Answer 2

Concept:

The root of a equation involving a variable suggests that the numerical value of the variable which satisfies that equation.

Given:

Given the equation is (x+4)/4 + (x-5)/3 = 11

Find:

The root of the above given equation.

Solution:

Given the equation is, (x+4)/4 + (x-5)/3 = 11

On solving the given equation we get,

(x+4)/4 + (x-5)/3 = 11

((x+4)*3+(x-5)*4)/12 = 11, since LCM of 4,3 = 12

(3x+12+4x-20)/12 = 11

(7x-8)/12 = 11

7x-8 = 11*12, multiplying 12 with both sides

7x-8 = 132

7x = 132+8

7x = 140

x = 140/7

x = 20

So the root is x=20

Hence the root of the given mathematical equation (x+4)/4 + (x-5)/3 = 11 is given by x = 20.

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