Question

using factor theorm ,factorize each of them 1)x^3-6x^2+3x+10

Answer 1

HEYA !!



p(x) = x³-6x²+3x+10
p(1) = 1-6+3+10 ≠0
p(-1) = -1-6-3+10=0

First factor is (x+1)
g(x)=(x+1)

Dividing p(x) by g(x), quotient is x²-7x+10

Now splitting the middle term:

x²-7x+10
x²-5x-2x+10
(x²-5x)(-2x+10)
x(x-5)-2(x-5)
(x-2)(x-5)

Total factors are :
(x+1)
(x-2)
(x-5)