using factor theorm ,factorize each of them 1)x^3-6x^2+3x+10
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HEYA !!
p(x) = x³-6x²+3x+10
p(1) = 1-6+3+10 ≠0
p(-1) = -1-6-3+10=0
First factor is (x+1)
g(x)=(x+1)
Dividing p(x) by g(x), quotient is x²-7x+10
Now splitting the middle term:
x²-7x+10
x²-5x-2x+10
(x²-5x)(-2x+10)
x(x-5)-2(x-5)
(x-2)(x-5)
Total factors are :
(x+1)
(x-2)
(x-5)
p(x) = x³-6x²+3x+10
p(1) = 1-6+3+10 ≠0
p(-1) = -1-6-3+10=0
First factor is (x+1)
g(x)=(x+1)
Dividing p(x) by g(x), quotient is x²-7x+10
Now splitting the middle term:
x²-7x+10
x²-5x-2x+10
(x²-5x)(-2x+10)
x(x-5)-2(x-5)
(x-2)(x-5)
Total factors are :
(x+1)
(x-2)
(x-5)
fathimapathukun:
thanks alot
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