If the zeroes of the polynomial x 3 -3x 2 +x+1 are alpha - beta , alpha , alpha + beta . Find alpha and beta
Arshia29:
can u write the polynomial clearly so that i can solve it. i can not understand which one is multiplication sign an which one is variable "x"
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x³-3x²+x+1=0, think gamma=Δ
given,α+β+Δ=α-β
αβ+βΔ+Δα=α
αβΔ=α+β
we know that, α+β+Δ=-b÷a
αβ+βΔ+Δα=c÷a
αβΔ=-d÷a
substitute the values,
⇒ α-β =b÷a= -(-3)÷1=3
⇒α-β=3--------------------------------eq 1
⇒α+β=d÷a= -1÷1= -1
⇒α+β= -1-----------------------------eq 2
eq 1-----------⇒α - β = 3
eq 2-----------⇒α+ β = -1
(-) (-) (+)
-------------------
⇒ -2β=4
⇒ β= -2
substitute β in eq 1,
⇒α-β=3
⇒α-(-2)=3
⇒α+2=3
⇒α=1
given,α+β+Δ=α-β
αβ+βΔ+Δα=α
αβΔ=α+β
we know that, α+β+Δ=-b÷a
αβ+βΔ+Δα=c÷a
αβΔ=-d÷a
substitute the values,
⇒ α-β =b÷a= -(-3)÷1=3
⇒α-β=3--------------------------------eq 1
⇒α+β=d÷a= -1÷1= -1
⇒α+β= -1-----------------------------eq 2
eq 1-----------⇒α - β = 3
eq 2-----------⇒α+ β = -1
(-) (-) (+)
-------------------
⇒ -2β=4
⇒ β= -2
substitute β in eq 1,
⇒α-β=3
⇒α-(-2)=3
⇒α+2=3
⇒α=1
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