Question

If the zeroes of the polynomial x² - lx + m are -2 and 3. Find l and m.( l = 1, m = -6 )​

Answer 1

Answer:

l=1,m=-6

Step-by-step explanation:

p(x)=x^2 - lx = m

zeroes:- -2 and 3

p(-2)=(-2)^2 + 2l + m

         4+2l+m=0       -------  1)

p(3)=9-3l+m=0        ---------- 2)

1) and 2) are equal to 0

4 + 2l + m = 9 - 3l +m

5l = 5

l=5

let take equation 1) for value of m

4 + 2(1) + m = 0                                      (l=1)

6+m=0

m=-6

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Answer 2

As x=-2 therefore(-2)^2+2l+m=0
4+2l+m =0
m= -4 -2l
As x=3 so 9-3l+m=0
m=3l-9
Therefore-4-2l=3l-9
-2l-3k=_9+4
-5l =-5
l=1 and m=3*1-9=-6