if the zeroes of the polynomial x3-3x2+X+1 ARE a-b,a,a+b,find a and b
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sum of roots =-b/a
a-b + a + a+ b = -(-3)
3a =3
a=1
product of all -
a(a-b)(a+b) =-1
a(a² - b²) =-1
put in it a=1
1(1-b²) =-1
1 - b² = -1
-b² =-2
b² = 2
b= ±√2
a-b + a + a+ b = -(-3)
3a =3
a=1
product of all -
a(a-b)(a+b) =-1
a(a² - b²) =-1
put in it a=1
1(1-b²) =-1
1 - b² = -1
-b² =-2
b² = 2
b= ±√2
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