Question

If the zeroes of the quadratic polynomial $x^2+(a+1)x+b$ are 2 and -3, then, (a) a = -7 , b =1 (b) a =5 : b =-1 (c) a = 2 , b = -6 (d) a =0 , b =-6

Answer 1

Answer:

hope this will help you mate

Answer 2

Answer:

As alpha and beta are the zeroes of the quadratic polynomial x²+2x+1=0

Alpha + beta=-2

Alpha × beta= 1

Alpha²beta+ beta²alpha= alpha beta(alpha + beta)

=-2×1

=-2

Step-by-step explanation:

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