If the zeroes of the quadratic polynomial x + (a+1)x+b are 2 and -3 , then find the value of a and b.
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» x² + (a + 1)x + b
» - (a + 1) = -3 + 2
» a = 0 & » b = - 6
Therefore, the values of a and b are 0 and -6.
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