If the zeroes of the quadratic polynomial x² + (0+1)x+b are 2 and -3, then
(A) a = -7, b = -1
(C) a = 2, b = -6
(B) a = 5, b = -1
(D) a=0,b=-6
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1
Answer:
Correct option is
D
a=0,b=−6
x
2
+(a+1)x+b is the quadratic polynomial.
2 and −3 are the zeros of the quadratic polynomial.
Thus, 2+(−3)=
1
−(a+1)
=>
1
(a+1)
=1
=>a+1=1
=>a=0
Also, 2×(−3)=b
=>b=−6
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