Question

If the zeroes of the quadratic polynomial x² + (a+1)x+b are 2 and -3, then

(a) a=-7,b=-1
(b) a=5 ,b=-1
(c) a=2,b=-6
(d) a=0,b=-6


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Answer 1

a= 2 b=-6

Step-by-step explanation:

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Answer 2

Answer:

(d) a=0, b = - 6

Step-by-step explanation:

sum of zeroes = - ( coefficient of x) / coefficient of x^2

2+ ( - 3 ) = - (a+ 1) / 1

-1 = - a - 1

- 1 + 1 = - a

0 = - a

0 = a

product of zeroes = constant term / coefficient of x^2

2 × ( - 3 ) = b / 1

- 6 = b