Question

If the zeroes of the quadratic polynomial x2 + (a+1) x + b are -2 and 3 then find the value of a and b.

Answer 1

Step-by-step explanation:

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one of the zero is -3 that means x = -3

quadratic equ

(k - 1) {x}^{2} + x + 1 = 0(k−1)x

2

+x+1=0

putting x = -3

(k - 1) {( - 3)}^{2} + ( - 3) + 1 = 0(k−1)(−3)

2

+(−3)+1=0

(k - 1)9 - 3 + 1 = 0(k−1)9−3+1=0

9k - 9 - 3 + 1 = 0

9k - 12 + 1 = 0

9k - 11 = 0

9k = 11

k = 11/9

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