Math, asked by lakshitacr2006, 1 month ago

If the zeroes of the quadratic polynomial [x² +(a + 1) x + b] are 2 and -3, then
None
a = 2, b = -6
a = 0, b = -6
a = 5, b = -1
a = -7, b = -1​

Answers

Answered by gauthmathakash
1

Answer:

Step-by-step explanation:

answer is option b

a=0,b= -6

According to the problem statement, we are given a quadratic polynomial x2+(a+1)x+b having 2 and -3 as zeroes. Therefore, α=2 and β=−3.

ANSWERED BY GAUTHMATH

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