Question

if the zeroes of x2-kx+6 are in the ratio 3:2 find k

Answer 1

Here's your answer

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Let the zeroes be 3y and 2y

Product=> 3y×2y=6y²= c/a

6y²=6/1

y²=6/6

y²=1

y=1

So, Zeroes=3y=3×1=3, 2y=2×1=2

Sum=>3+2=5= -b/a

5= -(-k)/1

5=k/1

Answer==> k=5

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Hope it helps✌

Answer 2

let first zero be = 3y

let second zero be= 2y

sum of zeroes = α +β = -b/a

3y + 2y = -k / 1

5y + k = 0 ........1

Product of zeroes =αβ = c/a

6y = 6

y = 1

Putting y=1 in equation 1

5+ k=0

k=-5