Question

If the zeros of a quadratic polynomial are 4 and 2 , find the polynomial

Answer 1

Answer: x²-6x+8

Step-by-step explanation:

α = 4 and β = 2

so as using the formula

x²- ( sum of zeros) x+ product of zero

also written in form of ( x²-(α + β )x + (αβ))

x²-(4+2)x+8

= x²-6x+ 8

Answer 2

Answer:

$\text{Required polynomial is }x^2-6x+ 8$

Step-by-step explanation:

Given the zeroes of a quadratic polynomial are 4 and 2

we have to find the polynomial.

α = 4 and β = 2  

By using formula,

$x^2- (\text{sum of zeros})x+ (\text{product of zeros})$  

$x^2-(4+2)x+8$

$x^2-6x+ 8$

∴ $\text{Required polynomial is }x^2-6x+ 8$