Question

if the zeros of a quadratic polynomial X square + 1750x+175000 are

A)both negative
B)one positive one negative
C)both positive
D)both equal​

Answer 1

Answer:

In this question you just have to find discriminant D of the given quadratic equation. Which is given by D = b^2 - 4ac

where b , a and c have their usual meanings.

On solving we get D = 2362500

here D is greater than 0.

A positive discriminant indicates that the quadratic has two distinct real number solutions.

Answer 2

Answer:

The correct answer will be -

(A) both negative

Step-by-step explanation:

Given polynomial is

$x^2+1750x+17500$

comparing to the general quadratic polynomial.

$ax^2+bx+c$

we get,

a = 1

b = 1750

c = 17500

calculating the value of D

$D = b^2 - 4ac$

$D = 1750^2 - 4\times1\times175000 = 2362500$

We got,

D > 0

So for this case, we will have two distinct real roots.

And, roots of a quadratic polynomial are given by,

$\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

To check whether the roots are positive or negative -

$\sqrt{b^2 - 4ac} = \sqrt{D} = 1537.04$

One root will be negative since $-b-\sqrt{D}$ will yield a negative number.

The other root will be $-b+\sqrt{D}$. We can see that the calculation will also yield a negative number.

So both the roots will be negative numbers.

#SPJ2