Question

if the zeros of a quadratic polynomial X square + A + 1 into X + b is 2 and minus 3 then find the value of a and b ​

Answer 1

Answer:

option d )  a = 0 and b = -6.

Step-by-step explanation:

given :

2 and -3 are the zeros of  P( x ) = $x^{2}+(a+1)x+b$

so,

P ( 2 ) = P ( -3 ) = 0

P ( 2 ) = $4+(a+1)2+b = 0$

           $2a + b=-6$ --------------------------------------- ( 1 )

P ( -3 ) = $9+(a+1)(-3)+b = 0$

           = $3a-b=6$ ----------------------------------------( 2 )

solving equations 1 and 2, you get....

a = 0 and b = -6.

Thus you got the answer.

Hope it helps !