If the zeros of polynomial f(x)=2xcube-15xsquare+37x-30 are in A.P, find them
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Answered by
6
Let a- d, a , a + d are the 3 zeros of the polynomial are in A.P.
a - d + a + a + d = -(-15)/ 2 = 15 / 2
3a = 15 / 2.
a = 5 / 2
(a - d)a(a + d) = -(-30) / 2
a(a2 - d2) = 15
(5/2)(25/ 4 - d2) = 15
(25/ 4 - d2) = 6
d2 = (25/ 4 - 6) = 1 / 4.
d = ±1 / 2.
∴ The zeros are (5/2 - 1/2), 5/ 2 , (5/2 + 1/2)
2, 5/2, 3
Answered by
11
Answer:
The zeros are 2 , 5/2=2.5 and. 3 because it is in AP of common differences =0.5 ...
....hope it's helpful...................... thanks.
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