if the zeros of polynomial x3-3x2+x+1are a-b ,a,a+b. value of a is
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sum of the zeroes = -b/a
a -b+a+a+b=-(-3)/1
3a=3
therefore,a equals 1
a -b+a+a+b=-(-3)/1
3a=3
therefore,a equals 1
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Here a is 1...since only by replacing x by 1 we get the eqn. equal to zero . I m not exactly sure but hope it's correct....by the way ...are the answers are given...then what's the answer..
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