if the zeros of polynomial x³-6x²-8x+24 is in the form of a-b , a and a+b then find all zeros can anybody answer this question if you are brilliant then answer this
Answers
The zero of a polynomial is a value of the variable at which the polynomial equals 0 .
For the said polynomial, we have these equations:
1..
a3−3a2+a+1=0
2...
(a−b)3−3(a−b)2+a−b+1=0
or,a3−3a2b+3ab2−b3−3a2+6ab−3b2+a−b+1=0
3...
(a+b)3−3(a+b)2+a+b+1=0
or,a3+3a2b+3ab2+b3−3a2−6ab−3b2+a+b+1=0
Using equations 1 & 2, we get,
−3a2b+3ab2−b3−3b2+6ab−b=0
or, 3a2b−3ab2+b3+3b2−6ab+b=0
Using equations 1 & 3, we get,
3a2b+3ab2+b3−3b2−6ab+b=0
Subtracting last two equations, we get,
6ab2−6b2=0
or, 6b2(a−1)=0
or, b=0, or a=1
Now, putting a=1 in either equation 1 or equation 2, we get,
3b+3b2+b3−3b2−6b+b=0
or, b3−2b=0
or, b(b2−2)=0
or, b=0 , or b √2 or b= -√2
So, we have got a=1 and b = 0, √2 nd -√2
Therefore, the zeroes of the said polynomial are
1,1 + √2 and 1−√2
.
Question :
If the zeroes of the polynomial x³-6x²-8x+24 is in the form of α-β , α , α+β then find all zeroes
Solution :
We are given a cubic polynomial x³-6x²-8x+24 and roots/zeroes of the poly. is α-β , α , α+β
Compare given cubic poly. with ax³+bx²+cx+d ,
- a = 1 , b = -6 , c = -8 , d = 24
Sum of zeroes of the poly. is ,
Product of zeroes of the poly. is ,
- ( a + b ) ( a - b ) = a² - b²
- α = 2
So , Zeroes of the polynomial are as follows ,
(α-β) = (2-4) = -2 or (α-β) = (2-(-4)) = 6
- α = 2
(α+β) = (2+4) = 6 or (α+β) = (2+(-4)) = -2
-2 , 2 , 6 are zeroes of the polynomial
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