Question

if the zeros of quadratic polynomail x2+(a+1)x+b are 2 and -3 then find the value of a and b

Answer 1

Answer:

a =  0  b = - 6

Step-by-step explanation:

If A and B are the roots of a Quadratic Polynomial then The Q.E. is given by

$x^2-(A+B)x+AB=0$

$GIVEN\\\\A=2\\B=-3\\and\;\;Q.E. \;\;is\\x^2+(a+1)x+b=0$

On Comparison

a + 1 = - ( A + B )

b = AB

=> a + 1 = - ( 2 - 3 )

=> a + 1 = - ( - 1 )

=> a + 1 = 1

=> a = 0

=> b = AB

=> b = 2 x ( - 3 )

=> b = - 6

HOPE IT HELPS