Question

"If the zeros of the polynomia!(x)= x -3x²+x+1 are a-b,a, a+b, find a and b​

Answer 1

Answer:

$sum \: of \: root = 3 = 3a \\ \\ a = 1 \\ \\ multiply \: of \: roots = (1 - b)(1)(1 + b) = - 1 \\ \\ 1 - {b}^{2} = - 1 \\ \\ {b}^{2} = 2 \\ \\ b = \sqrt{2}$