if the zeros of the polynomial x^2 + 4 x + 2a are alpha and 2/beta , then find the value of a
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Answer:
Comparing x2+4x+2a with ax2+bx+c,
a=1,b=4,c=2a
According to the question,
α,2α are the zeroes of the polynomial,
sum of the zeroes ab
α+2α=1−4
α=3−8
α2=964 [squaring both sides]
product of all zeroes,
α×2α=12aα2=4a
∴4a=964 [∵α2=964]
a=916
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Pls mark as brainliest answer
a=alpha/beta.
a=alpha/beta.
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