Question

if the zeros of the polynomial x^2-8x+K =0 are the HCF of 6,12 , then find the value of k

ans-3​

Answer 1

Correct Question:-)

lf the zeros of the polynomial x^2-8x+K are HCF of 6 ,12 then find the value of k.

(if we put equality sign then it will become an equation)

Solution:-)

Firstly

we have to calculate HCF of 6 , 12

As,

6 = 2 × 3 .

12 = 2 × 2 × 3

So,

HCF of 6, 12 is 2 × 3 = 6 .

lt is provided that zero of the polynomial

${x}^{2} - 8x + k$

is HCF of 6 and 12.

So,

zero of the polynomial is 6.

And after putting 6 at place of X in the given polynomial the polynomial will become zero i.e.

36 - 48 + k = 0

k = 12 .

Answer 2

Answer:

Step-by-step explanation: