Question

If the zeros of the polynomial x^3-3x^2+2 are a-b, a, a+b find a and b

Answer 1

zeroes of the polynomial are the roots of polynomial
there fore a-b,a,a+b are the roots
in the polynomial $x^{3}-3 x^{2} +2=0$ 
$S_{1}$ = $x_{1} + x_{2} + x_{3}$ = -b/a =a-b+a+a+b = -(-3)/1 = 3 
3a=3
a=1
S_{2} = $x_{1} x_{2} + x_{2} x_{3} + x_{3} x_{1}$ = c/a = a(a-b) + (a-b)(a+b) + a(a+b) = 0
$a^{2} -ab +a^{2} +ab +a^{2} - b^{2} = 0$
3a^2 - b^2 = 0
b =$\sqrt{3}$
1-$\sqrt{3}$,1,1+$\sqrt{3}$ are the zeroes of the given polynomial

Answer 2

Answer:

b =3 I hope this is helpful for you