Question

if the zeros of the quadratic polynomial X square + A + 1 into X + B are 2 and -3 then what is value of a and b​

Answer 1

Answer:

Given that zeros of the quadratic polynomial

${x}^{2} + (A + 1)x + B ................(i)$

are 2 and -3 .

So,

sum of zeros = 2 - 3= -1

and

product of the zeros = 2 × (-3) = -6

As we know that quadratic polynomial whose sum and product of zeros are given is of the form

${x}^{2} - sx + p$

where s and p are sum and product of roots respectively.

so this quadratic polynomial becomes

${x}^{2} + x - 6$

So,

On comparing with given(i) that is comparing coefficients of each term and constant we get that

$A + 1 = 1 \: \\ \implies A = 0$

and

$B = - 6$

So,

values of A and B will be 0 and -6 respectively .