Question

If the zeros of the quadratic polynomial x square + a + 1 x + b are two and minus 3 then find the value of a and b

Answer 1

Let polynomial be f(x)= x^2 + a + x + b - 3

Substitute x = 2 In Polynomial ;

f(x) = x^2 + a + x + b - 3

2^2 + a + 2 + b - 3 =0

4 + 2 -3 + a + b = 0

3+a + b = 0

a + b =- 3 ------(1)

Now, Substitute x = -3 In Polynomial ;

f(x) = x^2 + a + x + b - 3

(-3)^2 + a - 3 + b - 3 = 0

9 + a - 6 + b = 0

a + b = - 3 ------(2)

So , the value of a and b are 0 .