If the zeros of the quadratic polynomial x square + a + 1 x + b are two and minus 3 then find the value of a and b
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Let polynomial be f(x)= x^2 + a + x + b - 3
Substitute x = 2 In Polynomial ;
f(x) = x^2 + a + x + b - 3
2^2 + a + 2 + b - 3 =0
4 + 2 -3 + a + b = 0
3+a + b = 0
a + b =- 3 ------(1)
Now, Substitute x = -3 In Polynomial ;
f(x) = x^2 + a + x + b - 3
(-3)^2 + a - 3 + b - 3 = 0
9 + a - 6 + b = 0
a + b = - 3 ------(2)
So , the value of a and b are 0 .
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