If the zeros of x cube minus 3 X square + X + 1 are a minus b a and a + b then find a and b
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bhai bass ke bahar hai..
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Given:
p(x)= x³-3x²+x+1= 0
we know that sum of zeroes= -b/a
= a+(a-b)+(a+b)= 3
= 3a= 3
★a = 1
also,
Product of zeroes= c/a
a(a-b)(a+b)= 1
substitute the value of a=1
1(1-b)(1+b)=1
1-b²= 1
-b²= 2
★ b= ±√2
___________________
p(x)= x³-3x²+x+1= 0
we know that sum of zeroes= -b/a
= a+(a-b)+(a+b)= 3
= 3a= 3
★a = 1
also,
Product of zeroes= c/a
a(a-b)(a+b)= 1
substitute the value of a=1
1(1-b)(1+b)=1
1-b²= 1
-b²= 2
★ b= ±√2
___________________
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