Question

If thee velocity of a body is doubled while its mass is halved, what happens to its kinetic energy. Explain.

Answer 1

Answer:

Well, if mass is doubled, K. E is doubled

So now K.E1=2K.E

When velocity is halved, K.E becomes 1/4th of initial value

K.E 2 = K.E1 /4

=2*K.E/4

=K.E/2

so, kinetic energy is halved after the changes

Answer 2

Answer:

Explanation:

KE= 1/2 $mv^{2}$

v=2v

m=m/2

KE'=1/2 * m/2 * $(2v)^{2}$

KE'= $mv^{2}$

KE'/KE= $mv^{2}$ / 1/2 $mv^{2}$

So the new kinetic energy becomes twice of the initial Kinetic Energy