If theeta is complementary angle ,then sec theet is equal to......
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→ cosθ = sin(90-θ)
→ sinθ = cos(90-θ)
→ tanθ = cot(90-θ) = 1/cotθ
→ secθ = cosec(90-θ) = 1/cosθ
→ cosecθ = sec(90-θ) = 1/sinθ
→ cotθ = tan(90-θ) = 1/tanθ
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