Math, asked by devjob5227, 1 year ago

If there are 1000 chocolates in how many ways can you distribute them equally

Answers

Answered by bhumikapaliwal
0
divide it by the number is 10,25, 100,200 and 500 divide it 20
Answered by payalchatterje
0

Answer:

I can distribute 1000 chocolates by 16 ways

Step-by-step explanation:

Here total number of chocolates are 1000.

We need to find how many ways can you distribute them equally.

For solution,we need to know all factors of 1000.

By some examples, we can understand the concept more easily.

Example-1:

Let we have 20 apples.

Now factors of 20 are 20,10,5,4,2,1

So total by 6 ways,we can distribute 20 apples.

Example -2:

Let we have 100 pen.

Now factors of 100 are 100,50,25,20,10,5,4,2,1

So,total by 9 ways ,we can distribute 100 pen.

Here given total number of chocolates are 1000.

Now all factors of 1000 are 1000,500,250,200,125,100,50,40,25,20,10,8,5,4,2,1.

Here 1000 has total 16 factors.

Therefore I can distribute 1000 chocolates by 16 ways.

So,

1. 1 chocolate each to 1000 people.

2. 2 chocolates each to 500 people.

3. 4 chocolates each to 250 people.

4. 5 chocolates each to 200 people.

5. 8 chocolates each to 125 people.

and so on.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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