Question

if there are 2 no.s such that the sum of the number is 22 and the difference of their squares is 132.Find the difference​

Answer 1

Let the numbers be [math]x[/math] and [math]y[/math]

Answer 2

Answer:

Step-by-step explanation:

Let the numbers be x and y

hence, x+y=22

            x=22-y (eqn.1)

x^2-y^2=132

using the formula, a^2-b^2=(a+b)(a-b):-

(x+y)(x-y)=132

substituting eqn. 1:-

(22-y+y)(22-y-y)=132

22(22-2y)=132

22-2y=132/22=6

-2y=6-22

-2y=-16

hence,y=8

hence, x=22-8=14

But we do not know if x>y or y>x

so on solving y^2-x^2=132,

we get x=8 and y= 14

hence x=8,14

           y=14,8

Therefore the difference is 14-8 or 8-14=+6 or -6