Question

If there are 32 segments, each of size 1 kbytes, then the logical address should have:

Answer 1

answer is 15bits
ohhh good

Answer 2

If there are 32 segments, each of size 1 kbytes, then the logical address should have 15 bytes.

5 bytes are required to specify the logic segments, for example, 2^5=32. 10 more bytes are required to choose a certain specific byte from the logic segment. So the total number of bytes needed are 15.