Math, asked by kbajw66, 10 months ago

if there are three doors one door has gold behind it other 2 doors have donkeys behind it which door will you pick to find the gold? (door chosen least number of people will have gold) which=door.1, door.2, door.3

Answers

Answered by PushpeshPankaj
4

Probability of choosing a correct door = 1/3

Probability of choosing an incorrect door = 2/3

Suppose we say that the door is guessed correctly which makes no difference obviously the other two doors are always wrong.

probability of winning= 1/3 * 1 = 1

Suppose if its is guessed wrongly the other door is found to be correct.

probability of winning = 2/3*0 = 0

Again if suppose it is  guessed correctly. By changing the guess  probability of winning becomes 1/3 * 0 = 0.

If at all the guess is  incorrect. This means that the remaining door must be the correct one.

Probability of winning is 2/3 * 1 = 2/3.  

Total chances of winning by changing the guess is 2/3 + 0 = 2/3.

Answered by vijaytarun42
7

Step-by-step explanation:

if there are three doors one door has gold behind it other 2 doors have donkeys behind it which door will you pick to find the gold? (door chosen least number of people will have gold) which=door.1, door.2, door.3

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