Question

If there is an error of 2.1 in measuring the length of a simple pendulum then percentage error in its
period is
(A) 1%
(B) 2%
(C)3%
(D) 4%​

Answer 1

Step-by-step explanation:

Time period T=2π√l/g

dT/d1=π/√gl

Percentage error in measuring l = 2%

=>∆1/1 = 100/2

=>∆1=21/100

Approximate error in T =dT=(dT/d1)∆1

=T/100=1%ofT

Percentage error in T =1%

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