If theta=30, verify, sin 3 theta = 3 sin theta - 4 sin3 theta
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Given: Ф=30
To prove: sin3Ф=3sinФ-4sin^3Ф
Solution:
Taking RHS of the expression which we have to prove
3sinФ-4sin^3Ф
put the value of Ф=30° in the place of Ф
we get the value as 3sin(30)-4sin^3(30)
we know that the value of sin30=0.5....(1)
put the value of sin30 as 0.5 in (1)
we get,
on solving we get,
sin3Ф-4sin^3Ф=1
Now taking LHS which is sin3Ф
put the value of Ф as 30° in sin3Ф
we get,
=sin3(30)
=sin90°
we know that sin90° has a value of 1
hence,
sin3Ф=1 at Ф=30°....(3)
from (2) and (3) it is clear that sin3Ф-4sin^3Ф=sin3Ф
hence proved.
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