if theta= 30.veryfy tan 2theta= 2tantheta/1+tan^2yheta
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heya friend!!
"___________________
1st of all ur question is wrong at the place of 2tan¢/1+tan^2¢ it should be 2tan¢/1-tan^2¢
then ,
¢=30° [given]
and ,now from lhs
tan2¢
=)tan2*30°
=)tan60°=√3---------1)
and now from Rhs.
2tan¢/1+tan^2¢
=)2*tan30°/1+tan^2 30°
=)2*1/√3
--------------
1-*(1/√3)^2
=)2/√3
------------
3-1/3
=)√3 RHS ............1)
so from lhs 1) and Rhs 2) prooved.....
both are equal .......
hope it help you..
@rajukumar☺☺☺
so here
=)2*/√3
-----------
1+1/3
"___________________
1st of all ur question is wrong at the place of 2tan¢/1+tan^2¢ it should be 2tan¢/1-tan^2¢
then ,
¢=30° [given]
and ,now from lhs
tan2¢
=)tan2*30°
=)tan60°=√3---------1)
and now from Rhs.
2tan¢/1+tan^2¢
=)2*tan30°/1+tan^2 30°
=)2*1/√3
--------------
1-*(1/√3)^2
=)2/√3
------------
3-1/3
=)√3 RHS ............1)
so from lhs 1) and Rhs 2) prooved.....
both are equal .......
hope it help you..
@rajukumar☺☺☺
so here
=)2*/√3
-----------
1+1/3
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