if theta=30° prove cos2theta=cos2theta-sin2theta
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Answered by
3
let us take rhs :
cos2∅-sin2∅
cos60-sin60
(∅=30° and 2∅= 60°)
½-√3/2
=1-√3/2
=1/2
(approximately)
=cos60°
=cos2(30)°
=cos2∅
hence proved.
cos2∅-sin2∅
cos60-sin60
(∅=30° and 2∅= 60°)
½-√3/2
=1-√3/2
=1/2
(approximately)
=cos60°
=cos2(30)°
=cos2∅
hence proved.
Answered by
6
@ = 30°
Cos2@ = cos2(30) = cos 60° = 1/2
cos 2@ - sin 2@ = cos 60° - sin 60°
= 1/2 - √3/2 = (1 - √3)/2 which is nearly equal to 1/2.
So LHS = RHS.
Hope This Helps You!
Cos2@ = cos2(30) = cos 60° = 1/2
cos 2@ - sin 2@ = cos 60° - sin 60°
= 1/2 - √3/2 = (1 - √3)/2 which is nearly equal to 1/2.
So LHS = RHS.
Hope This Helps You!
Anonymous:
Cool !
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