If theta be an acute angle and 5cosec theta is equal to 7,then evaluate sin theta+cos^2-1
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Answer:
Step-by-step explanation:
Let, theta=a
5coseca=7
Coseca=7/5=h/p
i.e., h=7, p=5
b=√h2-p2
=√(7)2-(5)2
=√49-25
=√24
=4√6 cm
Now,
sina+cos2a-1
=p/h+(b/h)2-1
=5/7+(4√6/7)2-1
=5/7+16×6/49-1
=5/7+96/49-1
=35+96-49/49
=55/49
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