If theta equal 45 verify sin 2 theta equal 2sin.cos theta
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Here , I am using A instead
of theta.
A = 45° [ given ]
i ) Sin2A
= sin(2×45°)
= sin90°
= 1 ----( 1 )
ii ) 2sinAcosA
= 2sin45°cos45°
= 2×(1/√2)×(1/√2)
= 2/2
= 1 ----( 2 )
From (1 ) and (2) , we conclude
Sin2A = 2sinAcosA
••••
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