Question

if theta + fie = 45° , prove that (cot theta-1 )( cot fie - 1 ) = 2​

Answer 1

Step-by-step explanation:

as

$as \: \pi + theta = 45 \\ theta = 45 - \pi \\ put \: the \: value \: in \: lhs$

i write cot (45-phi)as 1/tan(45-phi)

then apply the identity of tan(a-b)=tana-tanb/1+tanatanb

thank you