if theta is a acute and sec^2 theta + sec theta=6 then find the value of theta
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let sec theta =x
the equation becomes
x^2 +x - 6=0
(x+3)(x-2)=0
x=-3,2
=>sec theta = -3,2
=>theta =secinverse -3 ,sec inversr 2
the equation becomes
x^2 +x - 6=0
(x+3)(x-2)=0
x=-3,2
=>sec theta = -3,2
=>theta =secinverse -3 ,sec inversr 2
mdfaiz16:
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