if theta is an acute angle and sin theta = cos theta, find the value of 2tan square theta + sin square theta - 1
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rajkumar981:
is the answer is sin^2theta
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hello there !!
i will be using A instead of theta
we have ,
sinA = cosA
=> sinA/cosA=cosA/cosA [divide both sides by cosA]
=> tanA=1 [since sinA/cosA=TanA]
=> tan45°=1
therefore A=45°
putting it in 2tan²A+sin²A-1
We get,
=> 2tan²45°+sin²45°-1
=> 2(1)²+ (1/√2)²-1
=>2+1/2-1=> (4+1-2)/2 => 3/2
hope this helped you ;)
i will be using A instead of theta
we have ,
sinA = cosA
=> sinA/cosA=cosA/cosA [divide both sides by cosA]
=> tanA=1 [since sinA/cosA=TanA]
=> tan45°=1
therefore A=45°
putting it in 2tan²A+sin²A-1
We get,
=> 2tan²45°+sin²45°-1
=> 2(1)²+ (1/√2)²-1
=>2+1/2-1=> (4+1-2)/2 => 3/2
hope this helped you ;)
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