Question

if theta is an acute angle and sin theta=cos theta,find the value of3tan^2+2sin^2theta-1

Answer 1

Answer:

Step-by-step explanation:

Answer 2

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sin theta = cos theta

so, sin theta = sin (90-theta) [since cos theta = sin90-theta]

so, theta = 90-theta

so, 2theta = 90

so, theta = 45

therefore, tan theta = 1

so, tan^2 theta = 1

and, sin theta =1/(2^1/2)

so, sin^2 theta = 1/2

Therefore, 3tan2 theta + 2 sin2 theta - 1 = 3(1) + 2(1/2) - 1

= 3 +1 -1

=3

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