the time period of a particle performing linear SHM is 12s . the time taken by it to make a displacement equal to half it's amplitude
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Answered by
3
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Dear Student,
Please find below the solution to the asked query:
Distance covered in one time period = 4× amplitude
Thus,
time taken to complete half the amplitude = 14×12time period
time taken = 18×12 = 1.5 s
Hope this information will clear your doubts about Simple Harmonic Motion.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
... ѕмαятαвнιѕнєк.........
ι нσρє уσυ нєℓρ !!!
Dear Student,
Please find below the solution to the asked query:
Distance covered in one time period = 4× amplitude
Thus,
time taken to complete half the amplitude = 14×12time period
time taken = 18×12 = 1.5 s
Hope this information will clear your doubts about Simple Harmonic Motion.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
... ѕмαятαвнιѕнєк.........
Answered by
0
Answer:
1 sec
Explanation:
To move from 0 to A/2, we have the equation:
T/12
T = 12 s in this case
So,
12/12 = 1 sec
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