Question

the time period of a particle performing linear SHM is 12s . the time taken by it to make a displacement equal to half it's amplitude

Answer 1

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Dear Student,
Please find below the solution to the asked query:


Distance covered in one time period = 4× amplitude 
Thus,

time taken to complete half the amplitude = 14×12time period
time taken = 18×12 = 1.5 s

Hope this information will clear your doubts about Simple Harmonic Motion.
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Answer 2

Answer:

1 sec

Explanation:

To move from 0 to A/2, we have the equation:

T/12

T =  12 s in this case

So,

12/12 = 1 sec